
Subtracting Multiple Logarithms - Mathematics Stack Exchange
Jun 1, 2016 · Subtracting Multiple Logarithms Ask Question Asked 9 years, 6 months ago Modified 9 years, 6 months ago
algebra precalculus - Rules for equation involving addition and ...
Oct 5, 2018 · When you raise the RHS $-\log x/2 + 2$ as the exponent using base 10, you get $10^ {-\log x/2 + 2}=10^ {-\log x/2}×10^2$ which is $100× (10^ {\log x})^ {-1/2}=100× (x)^ { …
Logarithm Subtraction and Division with Same Bases
Jan 18, 2020 · I'm rusty on logarithms. What is the approach to a problem like this? Any hints would be appreciated. I'm thinking the subtraction on the numerator and denominator can …
Dividing logs with same base - Mathematics Stack Exchange
From my understanding, if two logs have the same base in a division, then the constants can simply be divided i.e $125/25 = 5$ to result in $ {\log5} = 1.5$ but that is not the case as $ …
Addition/subtraction using logarithms - Mathematics Stack …
Nov 8, 2019 · I'm trying to figure out a way of handling numbers larger than $1.79 \\times 10^{308}$ in Javascript. The method I'm attempting is to store numbers as their base-10 …
Simplifying two logarithms with different bases
Aug 29, 2015 · I am being asked to simplify: $(\\log_4 7)(\\log_7 5)$ How can this be simplified given that the bases are different?
Adding logarithms with different bases - Mathematics Stack …
Apr 15, 2016 · Start asking to get answers Find the answer to your question by asking. Ask question
Why am I allowed to remove $\ln$ from both sides of an equation?
Mar 17, 2019 · When I have this equation: $\\ln(x+2) = \\ln(x^2)$, why can I just remove the $\\ln$ from both sides by raising it to the power of e. Does this not permanently change what the …
Solving Logs different bases? - Mathematics Stack Exchange
Solving Logs different bases? Ask Question Asked 9 years, 3 months ago Modified 5 years, 8 months ago
Simplification of different base logarithms - Mathematics Stack …
Nov 18, 2012 · I'm in doubt on simplifying the expression: $\\log_2 6 - \\log_4 9$ Working on it I've got: $\\log_2 6 - \\dfrac{\\log_2 9}{2}$ There's anyway to simplify it more ? I'm learning …